设减少x棵黄瓜秧苗,使得黄瓜收获最多,由题意得:y=(100-x)(x 1 ×0.1+2)=-0.1x2+8x+200,=-0.1(x-40)2+360,∴当x=40棵时,y最多=360千克.故答案为:40,360.